\(\frac{1}{rtd}\)=\(\frac{1}{r2}+\frac{1}{r2}+\frac{1}{r3}\)=\(^{\frac{1}{12}+\frac{1}{10}+\frac{1}{15}}\)=\(\frac{1}{4}\)Ω
=>rtđ=\(\frac{4}{1}\)=4Ω
u1=r1 \(\times\) i1=12\(\times\)0,2=2,4V
mà r1//r2//r3 nên u1=u2=u3=2,4V(đây là câu c luôn)
i2=\(\frac{u2}{r2}=\frac{2,4}{10}\)=0,24A
i3=\(\frac{u3}{r3}=\frac{2,4}{15}\)=0,16A