nSO2=4,48\22,4=0,2
24nMg+64nCu=8,8
2nMg+2nCu=2nSO2=0,4
⇒{nMg=0,1
nCu=0,1
%mMg=0,1.248,8.100=27,27%
%mCu=100−27,27=72,73%
nMg=nMgSO4=0,1
nCu=nCuSO4=0,1
mMgSO4=0,1.120=12g
mCuSO4=0,1.160=16g
\(n_{SO2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(2n_{Mg}+54n_{Cu}=8,8\)
\(2n_{Mg}+2n_{Cu}=2n_{SO2}=0,4\)
\(\Rightarrow\left\{{}\begin{matrix}n_{Mg}=0,1\left(mol\right)\\n_{Cu}=0,1\left(mol\right)\end{matrix}\right.\)
\(\%m_{Mg}=\frac{0,1.24}{8,8}.100\%=27,27\%\)
\(\%m_{Cu}=100\%-27,27\%=72,73\%\)
\(n_{Mg}=n_{MgSO4}=0,1\left(mol\right)\)
\(n_{Cu}=n_{CuSO4}=0,1\left(mol\right)\)
\(m_{MgSO4}=0,1.120=12\left(g\right)\)
\(m_{CuSO4}=0,1.160=16\left(g\right)\)
