Câu 18:
\(n_{NO}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\\ \text{Đ}\text{ặt}:n_{Al}=a\left(mol\right);n_{Fe}=b\left(mol\right)\left(a,b>0\right)\\ Al+4HNO_3\rightarrow Al\left(NO_3\right)_3+NO+2H_2O\\ Fe+4HNO_3\rightarrow Fe\left(NO_3\right)_3+NO+2H_2O\\ \Rightarrow\left\{{}\begin{matrix}a+b=0,15\\27a+56b=5,5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=0,1\\b=0,05\end{matrix}\right.\\ \Rightarrow\%m_{Al}=\dfrac{0,1.27}{5,5}.100\approx49,091\%;\%m_{Fe}\approx50,909\%\\ b,n_{HNO_3}=4.n_{NO}=0,6\left(mol\right)\\ V_{\text{dd}HNO_3}=\dfrac{0,6}{0,3}=2\left(M\right)\)
c) Dung dịch Y là dung dịch nào?
Đúng 2
Bình luận (0)
