Question

MÌNH ĐANG CẦN GẤP

DẠNG TOÁN BỎ NGOẶC RỒI THU GỌN BIỂU THỨC

a)-(a-c)-(a-b+c)

b)-(a-b+c)-(a+b+c)

c)(a+b)-(a-b)+(a-c)-(a+c)

d)(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

CẢM ƠN CÁC BẠN ĐÃ GIẢI GIÚP MIK^-^

Answer 1

a)\(-\left(a-c\right)-\left(a-b+c\right)\)

\(=-a+c-a+b-c\)

\(=\left(-a-a\right)+\left(c-c\right)+b\)

\(=-2a+b=0\)

\(-2a=b\)

b)\(-\left(a-b+c\right)-\left(a+b+c\right)\)

\(=-a+b-c-a-b-c\)

\(=\left(-a-a\right)+\left(b-b\right)+\left(-c-c\right)\)

\(=-2a+0=-2c\)

\(=-2a+-2c\)

c)\(\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)

\(=a+b-a+b+a-c-a-c\)

\(=\left(a-a+a-a\right)+\left(b+b\right)+\left(-c-c\right)\)

\(=0+2b+\left(-2c\right)\)

\(=2b+\left(-2c\right)\)

d)\(\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\)

\(=a+b-c+a-b+c-b-c+a-a+b+c\)

\(=\left(a+a+a-a\right)+\left(b-b-b+a\right)+\left(-c+c-c+c\right)\)

\(=2a+0+0\)

\(=2a\)

Answer 2

a)-(a-c)-(a-b+c)

=-a+c-a+b-c

=-2a+b

b)-(a-b+c)-(a+b+c)

=-a+b-c-a-b-c

=-2a-2c

=-2(a+c)

c)(a+b)-(a-b)+(a-c)-(a+c)

=a+b-a+b+a-c-a-c

=2b-2c

=2(b-c)

d)(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

=a+b-c+a-b+c-b-c+a-a+b+c

=2a

Answer 3

a,\(-\left(a-c\right)-\left(a-b+c\right)=-a+c-a+b-c=-2a+b\)

b,\(-\left(a-b+c\right)-\left(a+b+c\right)=-a+b-c-a-b-c=-2a-2c\)

c, \(\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)=a+b-a+b+a-c=a+2b-c\)

d, \(\left(a+b-c\right)+ \left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)=a+b-c+a-b+c-b-c+a-a+b+c=2a\)