Question

limx->1(căn(x+8)+căn(2x+2)-5x)/(x-1)

Answer 1

giải giúp mình vs

Answer 2

\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{x+8}+\sqrt{2x+2}-5x}{x-1}\\ =\lim\limits_{x\rightarrow1}\dfrac{\sqrt{x+8}-3+\sqrt{2x+2}-2+5-5x}{x-1}\\ =\lim\limits_{x\rightarrow1}\dfrac{x-1}{\left(x-1\right)\left(\sqrt{x+8}+3\right)}+\lim\limits_{x\rightarrow1}\dfrac{2\left(x-1\right)}{\left(x-1\right)\left(\sqrt{2x+2}+2\right)}+\lim\limits_{x\rightarrow1}\dfrac{5\left(1-x\right)}{x-1}\\ =\dfrac{1}{6}+\dfrac{1}{2}-5=-\dfrac{13}{3}\)