\(lim_{x\rightarrow1}\dfrac{3-2x^2-x^4}{5-3x-2x^2}=\)\(lim_{x\rightarrow1}\dfrac{\left(x^2-1\right)\left(x^2+3\right)}{2\left(x-1\right)\left(x+\dfrac{5}{2}\right)}=\)\(lim_{x\rightarrow1}\dfrac{\left(x+1\right)\left(x^2+3\right)}{2\left(x+\dfrac{5}{2}\right)}=\dfrac{\left(1+1\right)\left(1+3\right)}{2\left(1+\dfrac{5}{2}\right)}=\dfrac{8}{7}\)
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{3x^2+2x-1}-2}{x^2-1}\)
\(\lim\limits_{x\rightarrow1}\dfrac{x^3+3x^2-4}{x-1}\)
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{4x+5}+x}{\left(x^2+3x+2\right)}\)
\(\lim\limits_{x\rightarrow-3}\dfrac{x^3+27}{2x^2+3x-9}\)
tính giá trị \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{x^2-3x+6}+2x}{2x-3}\) ?
cho hàm số f(x) thỏa mãn: \(\lim\limits_{x\rightarrow1^+}f\left(x\right)=2\) và \(\lim\limits_{x\rightarrow1^-}f\left(x\right)=2\). tính giá trị \(\lim\limits_{x\rightarrow1}f\left(x\right)=?\)
cho f(x) là 1 đa thức thoa man \(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-16}{x-1}=24\). tính \(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-16}{\left(x-1\right)\left(\sqrt{2f\left(x\right)+4}+6\right)}\)
giới hạn \(\lim\limits_{x\rightarrow+\infty}\dfrac{\left(x-1\right)^2\left(2x^3+3x\right)}{4x-x^5}=\dfrac{a}{b}\). tìm a,b biết a/b tối giản
Tính:
\(\lim\limits_{x\rightarrow1}\dfrac{x+x^2+...+x^n-n}{x-1}\)
