ĐKXĐ: \(a>0\)
\(=\dfrac{a\sqrt{a}-a\sqrt{a}+a-\sqrt{a}}{\sqrt{a}\left(\sqrt{a}+1\right)\left(a-\sqrt{a}+1\right)}.\dfrac{a-\sqrt{a}+1}{3\left(\sqrt{a}-1\right)}\)
\(=\dfrac{\sqrt{a}\left(\sqrt{a}-1\right)}{\sqrt{a}\left(\sqrt{a}+1\right).3.\left(\sqrt{a}-1\right)}=\dfrac{1}{3\sqrt{a}+3}\)