\(\left\{{}\begin{matrix}\dfrac{x+y+1}{x+y}-\dfrac{x-y-1}{x-y}=0\left(1\right)\left(đk:x\ne\pm y\right)\\x+2y=3\left(2\right)\end{matrix}\right.\)
pt (2) <=> x = 3 - 2y
Thế (2) vào (1) ta có:
\(\dfrac{4-y}{3-y}-\dfrac{4-3y}{3-3y}=0\Leftrightarrow\dfrac{3y^2-15y+12-3y^2+13y-12}{3y^2-12y+9}=0\)
<=> -2y= 0 <=> \(y=0\)\(\Rightarrow x=3\)
Vậy hệ có nghiệm (3;0)
a,\(\left\{{}\begin{matrix}x^3+2y^2-4y+3=0\\x^2+x^2y^2-2y=0\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}\sqrt{x}+\sqrt{y}=7\\\sqrt{x-20}+\sqrt{y+3}=6\end{matrix}\right.\)
c, Tìm m để hệ phương trình \(\left\{{}\begin{matrix}mx^2+\left|x\right|-y=1-m\\x^2+y^2=1\end{matrix}\right.\)
giải hệ phương trình
\(\left\{{}\begin{matrix}\left(1-y\right)\sqrt{x-y}+x=2+\left(x-y-1\right)\sqrt{y}\\2y^2-3x+6y+1=2\sqrt{x-2y}-\sqrt{4x-5y-3}\end{matrix}\right.\)
( x; y thuộc R)
help me
#mã mã#
Giải hpt :
\(\left\{{}\begin{matrix}2\sqrt{x+3y+2}-3\sqrt{y}=\sqrt{x+2}\\\sqrt{y-1}-\sqrt{4-x}+8-x^2=0\end{matrix}\right.\)
giải hpt \(\left\{{}\begin{matrix}x^3+y^2=2\\x^2+y^3=2\end{matrix}\right.\)
giai he phuong trinh \(\left\{{}\begin{matrix}\sqrt{x+1}+\sqrt{y-1}=2+\sqrt{6}\\x+y=5+2\sqrt{6}\end{matrix}\right.\)
giải hệ \(\left\{{}\begin{matrix}\sqrt{7x+y}+\sqrt{2x+y}=5\\\sqrt{x+4y}+x-y=2\end{matrix}\right.\)
Giải hệ \(\left\{{}\begin{matrix}x^2\left(4y^2+1\right)+2\left(x^2+1\right)\sqrt{x}=6\\x^2y\left(2+2\sqrt{4y^2+1}\right)=x+\sqrt{x^2+1}\end{matrix}\right.\)
\(\begin{cases}4x^3-4x^2-7x=\left(3y^2-6y+4\right)\sqrt{3y^2-6y+7}\\\left(x^3-3x^2\right)\left(\sqrt{x^2+\left(y-1\right)^2}+3\right)+8=\left(x^2+y^2-2y\right)^2-7\left(x^2+y^2-2y\right)\end{cases}\)
\(\left\{{}\begin{matrix}\sqrt{5x^2+2xy+2y^2}+\sqrt{2x^2+2xy+5y^2}=3x+3y\\\sqrt{x+2y+1}+2\sqrt[3]{12x+7y+8}=2xy+x+5\end{matrix}\right.\)
