\(2x^2+y^2-3xy=x-y\)
\(\Leftrightarrow\left(x-y\right)\left(2x-y\right)=x-y\)
\(\Leftrightarrow\left[{}\begin{matrix}x-y=0\\2x-y=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}y=x\\y=2x-1\end{matrix}\right.\)
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