\(\left|3x+5\right|=\left|2x-1\right|\)
\(\Leftrightarrow\left|3x+5\right|-\left|2x-1\right|=0\)
Ta có hai trường hợp:
\(1)3x+5=2x-1\)
\(\Leftrightarrow x=-6\)
\(2)\left\{{}\begin{matrix}3x+5=0\\2x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3x=-5\\2x=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{-5}{3}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{-6;\dfrac{-5}{3};\dfrac{1}{2}\right\}\)
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