Question

Kết quả của phép tính \(\dfrac{x^2-4}{x^2-2x}\) . \(\dfrac{-3}{x+2}\) là :

Answer 1

\(=\left(x-2\right)\left(x+2\right)\left(-3\right)\)

Answer 2

=(x−2)(x+2)(−3)

Answer 3

\(\dfrac{x^2-4}{x^2-2x}.\dfrac{-3}{x+2}.\left(x\ne\pm2;x\ne0\right).\)

\(=\dfrac{\left(x-2\right)\left(x+2\right)}{x\left(x-2\right)}.\dfrac{-3}{x+2}=\dfrac{1}{x}.\left(-3\right)=-\dfrac{3}{x}.\)