\(\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{\dfrac{2}{3}-\dfrac{2}{7}-\dfrac{2}{13}}\cdot\dfrac{\dfrac{3}{4}-\dfrac{3}{16}-\dfrac{3}{64}-\dfrac{3}{264}}{1-\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}}-\dfrac{11}{8}\)
\(=\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{2\left(\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}\right)}\cdot\dfrac{\dfrac{3}{4}\left(1-\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}\right)}{1-\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}}-\dfrac{11}{8}\)
\(=\dfrac{1}{2}\cdot\dfrac{3}{4}-\dfrac{11}{8}\)
\(=\dfrac{3}{8}-\dfrac{11}{8}\)
\(=1\)
\(2^x+2^{x+3}-144=0\)
\(2^x+2^x\cdot2^3=144\)
\(2^x\left(1+2^3\right)=144\)
2^x=144/(1+8)
=>x=4
