PTHH: \(K+H_2O\rightarrow KOH+\dfrac{1}{2}H_2\uparrow\)
a_____________a______\(\dfrac{1}{2}\)a
Ta có: \(C\%_{KOH}=\dfrac{56a}{39a+80-2\cdot\dfrac{1}{2}a}=8\%\)
\(\Leftrightarrow a\approx0,121\left(mol\right)\) \(\Rightarrow m_K=0,121\cdot39=4,179\left(g\right)\)