theo đề bài:
\(Fe_3O_4+8HCl->2FeCl_3+FeCl_2+4H_2O\)
x...................8x..............2x................x.............4x(mol)
\(FeCl_2+2NaOH->Fe\left(OH\right)_2\downarrow+2NaCl\)
x....................2x..................x.....................2x(mol)
\(FeCl_3+3NaOH->Fe\left(OH\right)_3\downarrow+3NaCl\)
2x..................6x.................2x....................6x(mol)
\(HCl+NaOH->NaCl+H_2O\)
(y-x)........(y-x).................(y-x)........(y-x)(mol)
\(Fe\left(OH\right)_2->FeO+H_2O\)
x........................x............x(mol)
\(4FeO+O_2->2Fe_2O_3\)
x..............................0,5x(mol)
\(2Fe\left(OH\right)_3->Fe_2O_3+3H_2O\)
2x...............................x...........3x(mol)
\(m_{Fe_2O_3}=0,5x.160+160x=24=>240x=24\)
\(m_{Fe_2O_3}=0,5x.160+160x=24=>240x=24\)
mFe2O3=0,5.x.160+160x=24
=>240x=24
=>x=0,1(mol)
mFe3O4=0,1.232=23,2g
Fe3O4+4CO->3Fe+4CO2
0,1............0,4.....0,3.....0,4(mol)
nCO=0,4mol
mCO=0,4.28=11,2g
