Zn+2HCl-->ZnCl2+H2
0,1-------------0,1---0,1 mol
nZn=6,5\65=0,1 mol
=>VH2=0,1.22,4=2,24 l
=>mZnCl2=0,1.136=13,6 g
Câu hỏi của bảo nam trần ấy kéo xuống dưới
Bạn tìm link này nek:https://hoc24.vn/hoi-dap/tim-kiem?q=cho+6,5+gam+Zn+t%C3%A1c+d%E1%BB%A5ng+v%E1%BB%9Bi+dung+d%E1%BB%8Bch+axit+clohidric+(HCL),+thu+%C4%91%C6%B0%E1%BB%A3c+mu%E1%BB%91i+k%E1%BA%BDm+clorua+(ZnCl2)+v%C3%A0+kh%C3%AD+H2.++a,L%E1%BA%ADp+ph%C6%B0%C6%A1ng+tr%C3%ACnh+h%C3%B3a+h%E1%BB%8Dc+c%E1%BB%A7a+ph%E1%BA%A3n+%E1%BB%A9ng++b,T%C3%ADnh+kh%E1%BB%91i+l%C6%B0%E1%BB%A3ng+c%E1%BB%A7a+k%E1%BA%BDm+clorua+(ZnCl2)+t%E1%BA%A1o+th%C3%A0nh.&id=483318