nNa2O = \(\dfrac{23}{310}\) ( mol )
Na2O + H2O \(\rightarrow\) 2NaOH
\(\Rightarrow\) mNaOH = \(\dfrac{23}{310}\).40 = \(\dfrac{92}{31}\) (g)
\(4Na+O_2\underrightarrow{t^o}2Na_2O\)
\(\Rightarrow\) mNa = \(\dfrac{23}{155}\).23 = \(\dfrac{529}{155}\) (g)