1.N=2L:3.4=3000(nu) theo đề : ta có hệ 2A=2/3 * 3G 2A+2G=3000 -> A=T=G=X=750= 50% H=2A+3G=3750 2. 2A+3G=3750 N=3000-(153*2:3,4)=2910=2A+2G -->A=615=21.13%=T G=840 =28,87%=X 3. xét gen 2 A1=2/5 * 615=246-> T1=615-246=369 G1=2*A1=492 ->X1=840-492=348Câu trả lời: 1.N=2L:3.4=3000(nu) theo đề : ta có hệ 2A=2/3 * 3G 2A+2G=3000 -> A=T=G=X=750= 50% H=2A+3G=3750 2. 2A+3G=3750 N=3000-(153*2:3,4)=2910=2A+2G -->A=615=21.13%=T G=840 =28,87%=X 3. xét gen 2 A1=2/5 * 615=246-> T1=615-246=369 G1=2*A1=492 ->X1=840-492=348