\(n_{SO2}=\frac{0,15}{n_{OH}}=0,5.\left(0,2+0,2\right)\Rightarrow\) Tạo 2 muối
\(n_{SO2/3}=\frac{a}{n_{HSO3}}=b\)
\(\left\{{}\begin{matrix}a+b=0,15\\2a=b=0,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,05\\b=0,1\end{matrix}\right.\)
mmuối = mNa+ + mK+ + mSO2/3 + mHSO3
\(\Rightarrow m_{muoi}=0,1.23+0,1.39.80+0,1.81=18,3\left(g\right)\)