\(a,\widehat{AOx}+\widehat{BOy}+\widehat{AOB}=\widehat{xOy}=90^0\\ \Rightarrow\widehat{AOB}=90^0-30^0-30^0=30^0\\ \Rightarrow\widehat{AOB}=\widehat{AOx}=\widehat{BOy}\\ \Rightarrow OA.là.p/g.\widehat{BOx}\)
\(b,\widehat{BOC}=\widehat{COy}+\widehat{yOB}=\widehat{AOy}+\widehat{AOx}=\widehat{xOy}=90^0\\ \Rightarrow OB\perp OC\)