a) \(R_{td}=\dfrac{R_1.R_2}{R_1+R_2}=\dfrac{12.28}{12+28}=8,4\Omega\)
b) \(U=I.R_{td}=1,8.8,4=15,12\left(V\right)\)
\(U=U_1=U_2=15,12\left(V\right)\)
\(I_1=\dfrac{U_1}{R_1}=\dfrac{15,12}{12}=1,26\left(A\right)\)
\(I_2=I-I_1=1,8-1,26=0,54\left(A\right)\)
Đúng 2
Bình luận (0)