Nguyễn Huy Tú soyeon_Tiểubàng giải Akai Haruma
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Đại số lớp 6
Các câu hỏi tương tự
a)x=\(\dfrac{1}{4}+\dfrac{2}{13}\)
b)\(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
c)\(\dfrac{-8}{3}+\dfrac{-1}{3}\le x\le\dfrac{-2}{7}+\dfrac{-5}{7}\)
d)\(\dfrac{-5}{6}+\dfrac{8}{3}\dfrac{29}{-x}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
Bài 1. Tính giá trị biểu thức
125%.(dfrac{-1}{2})^2:(1dfrac{5}{16}-1,5)+2008^0
dfrac{2}{3.5}+dfrac{2}{5.3}+dfrac{2}{7.9}+dfrac{2}{9.11}+dfrac{2}{11.13}+dfrac{2}{13.15}
Bài 2. Tìm x, biết
x:3dfrac{1}{15}1dfrac{1}{12}
dfrac{3}{4}.x27
x.dfrac{1}{4}dfrac{5}{8}.dfrac{2}{3}
left(x+dfrac{1}{4}right):dfrac{3}{7}dfrac{1}{6}
dfrac{3}{4}-2.|2x-dfrac{2}{3}|2
dfrac{2}{3}x-dfrac{1}{2}xdfrac{5}{2}
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Bài 1. Tính giá trị biểu thức
125%.\((\dfrac{-1}{2})^2\):\((1\dfrac{5}{16}-1,5)+2008^0\)
\(\dfrac{2}{3.5}+\dfrac{2}{5.3}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}+\dfrac{2}{13.15}\)
Bài 2. Tìm x, biết
x:\(3\dfrac{1}{15}=1\dfrac{1}{12}\)
\(\dfrac{3}{4}.x=27\)
\(x.\dfrac{1}{4}=\dfrac{5}{8}.\dfrac{2}{3}\)
\(\left(x+\dfrac{1}{4}\right):\dfrac{3}{7}=\dfrac{1}{6}\)
\(\dfrac{3}{4}-2.|2x-\dfrac{2}{3}|=2\)
\(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{2}\)
BT: Tìm x, biết:
a) \(2\dfrac{2}{3}x+3\dfrac{3}{4}x=\dfrac{385}{24}\)
b) \(-2\dfrac{2}{3}:x=1\dfrac{7}{9}:0.8\)
c) \(140\%+\dfrac{5}{3}x+2x=2280\)
d) \(-3\dfrac{1}{3}\cdot\left|x\right|=1\dfrac{1}{2}-2\dfrac{2}{3}\)
Tìm x, biết:
1. left(dfrac{2x}{5}+2right):left(-4right)-1dfrac{1}{2}
2. x. ( x + 1) 0
3. 2x - 16 40 + x
4. x : dfrac{5}{3} + dfrac{1}{3} dfrac{-2}{5}
5. 3dfrac{1}{2} - dfrac{1}{2} x dfrac{2}{3}
6. dfrac{x}{4}dfrac{9}{x}
7. dfrac{1}{3}+dfrac{1}{2}:x -0,25
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Tìm x, biết:
1. \(\left(\dfrac{2x}{5}+2\right):\left(-4\right)=-1\dfrac{1}{2}\)
2. x. ( x + 1) = 0
3. 2x - 16 = 40 + x
4. x : \(\dfrac{5}{3}\) + \(\dfrac{1}{3}\) = \(\dfrac{-2}{5}\)
5. 3\(\dfrac{1}{2}\) - \(\dfrac{1}{2}\) x = \(\dfrac{2}{3}\)
6. \(\dfrac{x}{4}=\dfrac{9}{x}\)
7. \(\dfrac{1}{3}+\dfrac{1}{2}:x=\) -0,25
Chứng minh rằng :
a)dfrac{1}{x}-dfrac{1}{x+a}dfrac{a}{xleft(x+aright)}
b)dfrac{1}{xleft(x+1right)}-dfrac{1}{left(x+1right)left(x+2right)}dfrac{2}{xleft(x+1right)left(x+2right)}
c)dfrac{1}{xleft(x+1right)left(x+2right)}-dfrac{1}{left(x+1right)left(x+2right)left(x+3right)}dfrac{3}{xleft(x+1right)left(x+2right)left(x+3right)}
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Chứng minh rằng :
a)\(\dfrac{1}{x}\)-\(\dfrac{1}{x+a}=\dfrac{a}{x\left(x+a\right)}\)
b)\(\dfrac{1}{x\left(x+1\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)}=\dfrac{2}{x\left(x+1\right)\left(x+2\right)}\)
c)\(\dfrac{1}{x\left(x+1\right)\left(x+2\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)\left(x+3\right)}=\dfrac{3}{x\left(x+1\right)\left(x+2\right)\left(x+3\right)}\)
BT3: Tìm x, biết:
7) \(\dfrac{-5}{17}+\dfrac{3}{17}\le\dfrac{x}{17}\le\dfrac{13}{17}+\dfrac{-11}{17}\)
8) \(\dfrac{2}{3}\left(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{3}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\)
bài 1: tìm x bt:
a\(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
b, \(5\dfrac{4}{7}:x=13\)
c, (2 và 4/5.x-50) :2/3= 51
d,\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
e, \(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{12}\)
giúp mk nhs!!!!!!!!!!
\(\dfrac{-3}{4}x\dfrac{4}{7}+\dfrac{-3}{5}x\dfrac{3}{7}-\dfrac{2}{5}\)
\(\left(\dfrac{3}{4}x\dfrac{5}{6}-\dfrac{7}{12}\right)x\left(\dfrac{-12}{7}\right)\)
\(1,4x\dfrac{15}{19}x\left(\dfrac{4}{5}x\dfrac{-2}{3}\right)+\dfrac{7}{15}\)
Tính nha
Tìm x
a. \(x-\dfrac{20}{11.13}-\dfrac{20}{13.15}-\dfrac{20}{15.17}-...-\dfrac{20}{53.55}\)
b. \(\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2}{9}\)