Question

giúp mk

Answer 1

18

mk ko rảnh nên mk sẽ giải sau nhé!

Answer 2

Ta có: \(f\left(x\right)=\frac{-3}{x^2}\)

\(\Rightarrow f\left(-1\right)=\frac{-3}{\left(-1\right)^2}=\frac{-3}{1}=-3\)

\(g\left(x\right)=-4x\Rightarrow g\left(2\right)=-8\Rightarrow2g\left(-2\right)=-16\)

\(h\left(x\right)=x^2+5\Rightarrow h\left(0\right)=0+5=5\)

\(\Rightarrow f\left(-1\right)-2g\left(2\right)+h\left(0\right)=-3+16+5=18\)

Vậy \(f\left(-1\right)-2g\left(2\right)+h\left(0\right)=18\)

Answer 3