Question

Giúp mk vs nha

Rút gọn

(x^2+2x)^2-x(x^3-3x)+(x-3)(x+3)

Answer 1

\(\left(x^2+2x\right)^2-x\left(x^3-3x\right)+\left(x-3\right)\left(x+3\right)\)

\(=x^4+4x^3+4x^2-x^4+3x^2+x^2-9\)

\(=4x^3+8x^2-9\)

Chúc bạn học tốt!!!

Answer 2

\(\left(x^2+2x\right)^2-x\left(x^3-3x\right)+\left(x-3\right)\left(x+3\right)\\ =x^4+4x^3+4x^2-x^4+3x^2+x^2-9\\ =\left(x^4-x^4\right)+4x^3+\left(4x^2+3x^2+x^2\right)-9\\ =4x^3+8x^2-9\)

Answer 3

(x²+2x)² - x(x³-3x) + (x-3)(x+3)

= x⁴ + 4x² - x⁴ + 3x² + x² + 3x - 3x -9

= 8x² - 9