Bài 1:
Ta có: \(A=25\cdot7\cdot4+215\cdot35-217\cdot35\)
\(=20\cdot35+215\cdot35-217\cdot35\)
\(=35\left(20+215-217\right)\)
\(=35\cdot18=630\)
Bài 2:
a) Ta có: \(\left(-8\right)\cdot14\cdot125\)
\(=\left[\left(-8\right)\cdot125\right]\cdot14\)
\(=-1000\cdot14\)
\(=-14000\)
b) Ta có: \(-1\cdot2\cdot6\cdot25\cdot\left(-7\right)\cdot5\)
\(=7\cdot2\cdot6\cdot25\cdot5\)
\(=7\cdot\left(25\cdot6\right)\cdot\left(5\cdot2\right)\)
\(=7\cdot150\cdot10\)
\(=10500\)


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