a, \(x-\dfrac{2}{5}=\dfrac{5}{7}\)
\(x=\dfrac{5}{7}+\dfrac{2}{5}\)
\(x=\dfrac{39}{35}\)
Vậy ..............
b, \(-x-\dfrac{2}{3}=\dfrac{-6}{7}\)
\(-x=\dfrac{-6}{7}+\dfrac{2}{3}\)
\(-x=\dfrac{-4}{21}\)
\(\Leftrightarrow x=\dfrac{4}{21}\)
Vậy ...
-x=- \(\dfrac{6}{7}\)+\(\dfrac{2}{3}\)
-x =- \(\dfrac{4}{21}\)
=> x = \(\dfrac{4}{21}\)



