1)
nSO2=2,24\22,4=0,1(mol)
2NaOH+SO2→Na2SO3+H2O
nNaOH=2nSO2=0,1.2=0,2(mol)
CMNaoh=0,2\0,1=2M
2)
nCO2=5,6\22,4=0,25(mol)
nNaOH=1023+17=0,25(mol
Vì nNaOH :nCO2=1 ⇒⇒ Tạo ra muối axit
NaOH+CO2→NaHCO3
nNaOH=nCO2=nNaHCO3=0,25(mol)
⇒VCO2=0,25.22,4=5,6l