Câu 1:
\(n_{Cu\left(OH\right)_2}=\frac{m_{Cu\left(OH\right)_2}}{M_{Cu\left(OH\right)_2}}=\frac{49}{98}=0,5\left(mol\right)\)
Số phân tử Cu(OH)2 \(=0,5.6.10^{23}=3.10^{23}\left(phântử\right)\)
\(n_{CH_4}=\frac{V_{CH_4}}{24}=\frac{2,4}{24}=0,1\left(mol\right)\)
Số phân tử CH4 = 0,1.6.10^23=0,6.10^23(phân tử)
\(n_{SO_2}=\frac{V_{SO_2}}{22,4}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
Số phân tử SO2 = 0,1.6.10^23=0,6.10^23
Câu 2:
\(n_{H_2S}=\frac{m_{H_2S}}{M_{H_2S}}=\frac{17}{34}=0,5\left(mol\right)\)
\(V_{H_2S}=n_{H_2S}.22,4=0,5.22,4=11,2\left(l\right)\)
\(n_{CO_2}=\frac{4,2.10^{23}}{6.10^{23}}=0,7\left(mol\right)\)
\(V_{CO_2}=n_{CO_2}.22,4=0,7.22,4=15,68\left(l\right)\)
