a) Tự thụ phấn bắt buộc
Theo đề bài ta có: \(\frac{2}{3}\)AA:\(\frac{1}{3}\)Aa:0aa
Aa=\(\frac{\left(\frac{1}{3}\right)}{2^1}\)=\(\frac{1}{6}\)
AA=\(\frac{2}{3}+\frac{1-\frac{1}{2^1}}{2}.\frac{1}{3}\)=\(\frac{3}{4}\)
aa=\(0+\frac{1-\frac{1}{2^1}}{2}.\frac{1}{3}\)=\(\frac{1}{12}\)
\(\Rightarrow\)\(\frac{3}{4}AA:\frac{1}{6}Aa:\frac{1}{12}aa\)
b) Giao phối ngẫu nhiên
A=\(\frac{2}{3}+\frac{\left(\frac{1}{3}\right)}{2}=\frac{5}{6}\)
a=\(0+\frac{\left(\frac{1}{3}\right)}{2}=\frac{1}{6}\)
\(\Rightarrow\) \(\frac{25}{36}AA:\frac{5}{18}Aa:\frac{1}{36}aa\)