Đk \(x\ge0\)
Pt \(\Leftrightarrow\dfrac{2x+1-3x}{\sqrt{2x+1}+\sqrt{3x}}=x-1\)
\(\Leftrightarrow\dfrac{1-x}{\sqrt{2x+1}+\sqrt{3x}}+\left(1-x\right)=0\)
\(\Leftrightarrow\left(1-x\right)\left(\dfrac{1}{\sqrt{2x+1}+\sqrt{3x}}+1\right)=0\)
\(\Leftrightarrow1-x=0\)( vì \(\dfrac{1}{\sqrt{2x+1}+\sqrt{3x}}+1>0\) với mọi \(x\ge0\))
\(\Leftrightarrow x=1\)
Vậy S={1}