Question

Giải Pt tích

a) (3x – 2)\(\frac{2\left(x+3\right)}{7}-\frac{4x-3}{5}\) =0

b) (3,3-11x)\(\left(\frac{7x+2}{5}+\frac{2\left(1-3x\right)}{3}\right)=0\)

Answer 1

a) \(\left(3x-2\right)\left(\frac{10x\left(x+3\right)-7\left(4x-3\right)}{35}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-2=0\\-18x+51=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{2}{3}\\x=\frac{17}{6}\end{matrix}\right.\)

b)\(\left(3,3x-11\right)\left(\frac{3\left(7x+2\right)+10\left(1-3x\right)}{15}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{3}{10}\\x=\frac{16}{9}\end{matrix}\right.\)