ĐK : \(\left|x\right|\ge3\)
\(\sqrt{x^2-9}+\sqrt{x^2-6x+9}=0\)
\(\Leftrightarrow\sqrt{\left(x-3\right)\left(x+3\right)}+\sqrt{\left(x-3\right)^2}=0\)
\(\Leftrightarrow\sqrt{x-3}.\left(\sqrt{x+3}+\sqrt{x-3}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x-3}=0\\\sqrt{x+3}+\sqrt{x-3}=0\end{matrix}\right.\)
\(\Leftrightarrow x=3\) ( Thỏa mãn )