\(\dfrac{x+1}{9}+\dfrac{x+2}{8}=\dfrac{x+3}{7}+\dfrac{x+4}{6}\)
<=>\(\dfrac{x+1}{9}+1+\dfrac{x+2}{8}+1=\dfrac{x+3}{7}+1+\dfrac{x+4}{6}+1\)
<=>\(\dfrac{x+10}{9}+\dfrac{x+10}{8}-\dfrac{x+10}{7}-\dfrac{x+10}{6}=0\)
<=>\(\left(x+10\right)\left(\dfrac{1}{9}+\dfrac{1}{8}-\dfrac{1}{7}-\dfrac{1}{6}\right)=0\)
vì 1/9+1/8-1/7-1/6 khác 0
=>x+10=0<=>x=-10
vậy..............
các bạn giúp mình câu này với
giải phương trình sau: \(\dfrac{x+2}{x-2}\)-\(\dfrac{2}{x^2-2x}\)=\(\dfrac{1}{x}\)
mình cảm ơn nhiều ạ.
giải phương trình,giúp với ạ
\(\dfrac{x+1}{4}-\dfrac{5+2x}{8}=\dfrac{3-4x}{2}\)
\(\dfrac{4-3x}{5}-\dfrac{4-x}{10}=\dfrac{x+2}{2}\)
giải pt \(\dfrac{13}{\left(x-3\right)\left(2x+7\right)}+\dfrac{1}{2x+7}=\dfrac{6}{x^2-9}\)
Bài 1 : Giải PT
\(\dfrac{x-10}{1994}\)+\(\dfrac{x-8}{1996}\)+\(\dfrac{x-6}{1998}\)= \(\dfrac{x-2002}{2}\)+\(\dfrac{x-2000}{4}\)+\(\dfrac{x-1998}{6}\)
Bài 2: Giải PT
\(\dfrac{x-85}{15}\)+\(\dfrac{x-74}{13}\)+\(\dfrac{x-67}{11}\)+\(\dfrac{x-64}{9}\)=10
Giải các phương trình sau
1)\(\dfrac{x+1}{85}+\dfrac{x+3}{83}=\dfrac{x+5}{81}+\dfrac{x+7}{79}\)
2)\(\dfrac{x-1}{2015}-\dfrac{x+3}{2011}=\dfrac{x+7}{2007}-\dfrac{x+11}{2003}\)
3)\(\dfrac{x+4}{4}-\dfrac{x-3}{6}=\dfrac{x}{3}\)
4)\(x-\dfrac{x+1}{3}=\dfrac{2x+1}{5}\)
5) \(\dfrac{2x-7}{5}+\dfrac{x+11}{2}=-4\)
giúp em vs ạ, em đang cần gấp
em c.ơn trước ạ
Giải các phương trình:
\(a,\dfrac{2\left(x+7\right)}{x+1}-\dfrac{x+11}{x^2-1}=4-\dfrac{x-1}{x+1}\)
\(b,\dfrac{x+2}{x-3}+\dfrac{x+2}{x+3}=\dfrac{2\left(x+6\right)}{x^2-9}\)
a.\(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
b.\(x-\dfrac{2x-5}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)
c.\(\dfrac{x+1}{15}+\dfrac{x+2}{7}+\dfrac{x+4}{4}+6=0\)
d.\(\dfrac{x-342}{15}+\dfrac{x-323}{17}+\dfrac{x-300}{19}+\dfrac{x-273}{21}=10\)
e.\(\dfrac{x+97}{125}+\dfrac{x-63}{35}=\dfrac{x-7}{21}+\dfrac{x-77}{49}\)
giải các phương trình chứa ẩn
a) \(\dfrac{2\cdot\left(x^2+x+6\right)}{x^3-8}+\dfrac{2}{2-x}=\dfrac{3}{x^2+2x+4}\)
b) \(\dfrac{6}{x^3+1}-\dfrac{1-x}{x^2-x+1}=\dfrac{5}{x+1}\)
c) \(\dfrac{1}{x^2+3x+2}-\dfrac{3}{x^2-x-2}=\dfrac{-1}{x^2-4}\)
\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\) giải pt
