ĐKXĐ: \(x\ge\frac{1}{3}\)
\(\Leftrightarrow x^2+x\sqrt{3x-1}-2\left(3x-1\right)=0\)
\(\Leftrightarrow\left(x+2\sqrt{3x-1}\right)\left(x-\sqrt{3x-1}\right)=0\)
\(\Leftrightarrow x-\sqrt{3x-1}=0\)
\(\Leftrightarrow x=\sqrt{3x-1}\)
\(\Leftrightarrow x^2-3x+1=0\Rightarrow x=\frac{3\pm\sqrt{5}}{2}\)