\(\sqrt{x+\dfrac{3}{x}}-2=\dfrac{x^2+7}{2\left(x+1\right)}-2\)
\(\Leftrightarrow\dfrac{x+\dfrac{3}{x}-4}{\sqrt{x+\dfrac{3}{x}}+2}=\dfrac{x^2-4x+3}{2\left(x+1\right)}\)
\(\Leftrightarrow\dfrac{x^2-4x+3}{x\left(\sqrt{x+\dfrac{3}{x}}+2\right)}=\dfrac{x^2-4x+3}{2\left(x+1\right)}\)
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