\(\Leftrightarrow3x-x^2+12-4x=3\sqrt{x^2+x-2}\Leftrightarrow-\left(x^2+x-2\right)+10=3\sqrt{x^2+x-2}\)
đặt \(x^2+x-2=a\)
\(\Rightarrow-a+10=3\sqrt{a}\Leftrightarrow-a-3\sqrt{a}+10=0\Leftrightarrow\left(2-\sqrt{a}\right)\left(\sqrt{a}+5\right)=0\)
\(\Leftrightarrow a=4\)( TH \(\sqrt{a}+5=0\) luôn đúng nên ko xét)\(\Leftrightarrow x^2+x-2=4\Leftrightarrow x^2+x-6=0\Leftrightarrow\left(x-2\right)\left(x+3\right)=0\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
sai bạn sửa lại nhé
