\(\dfrac{x+1}{29}+\dfrac{x+3}{28}=\dfrac{x+5}{27}+\dfrac{x+7}{26}\)
<=>\(\dfrac{x+1}{29}+2+\dfrac{x+3}{28}+2=\dfrac{x+5}{27}+2+\dfrac{x+7}{26}+2\)
<=>\(\dfrac{x+59}{29}+\dfrac{x+59}{28}=\dfrac{x+59}{27}+\dfrac{x+59}{26}\)
<=>\(\left(x+59\right)\left(\dfrac{1}{29}+\dfrac{1}{28}-\dfrac{1}{27}-\dfrac{1}{26}\right)=0\)
vì 1/29+1/28-1/27-1/26 khác 0 =>x+59=0<=>x=-59
vậy....