Đặt \(\sqrt[4]{x}=a\)\(\ge0\), PT trở thành :
\(2a^4-a+\frac{3}{8}=0\Rightarrow16a^4-8a+3=0\)
\(\Rightarrow16a^4-8a^3+8a^3-4a^2+4a^2-2a-6a+3=0\)
\(\Rightarrow\left(2a-1\right)\left(8a^3+4a^4+2a-3\right)=0\)
\(\Rightarrow\left(2a-1\right)\left(8a^3-4a^2+8a^2-4a+6a-3\right)=0\)
\(\Rightarrow\left(2a-1\right)^2\left(4a^2+4a+3\right)=0\)
\(\Rightarrow a=\frac{1}{2}\)\(\Rightarrow x=\frac{1}{16}\)
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