a) \(x^2+x+\sqrt{3}x+\sqrt{3}=0\) <=> \(x\left(x+1\right)+\sqrt{3}\left(x+1\right)=0\) <=> \(\left(x+\sqrt{3}\right)\left(x+1\right)=0\) <=> x=\(-\sqrt{3}\) ; x=-1
b) tương tự câu a
a) \(x^2+x+\sqrt{3}x+\sqrt{3}=0\) <=> \(x\left(x+1\right)+\sqrt{3}\left(x+1\right)=0\) <=> \(\left(x+\sqrt{3}\right)\left(x+1\right)=0\) <=> x=\(-\sqrt{3}\) ; x=-1
b) tương tự câu a
Giải các phương trình sau:
a, \(16x^2-\left(1+\sqrt{3}\right)^2=0\)
b, \(x-2\sqrt{2x}+2=8\)
Giải phương trình :
a, \(x-\sqrt{2}+3\left(x^2-2\right)=0\)
b, \(x^2-5=\left(2x-\sqrt{5}\right)\left(x+\sqrt{5}\right)\)
Tìm x:
a) \(\left(5x-6\right)^2-\frac{1}{\sqrt{5x-7}}=x^2-\frac{1}{\sqrt{x-1}}\)
b) \(4x^3+x-\left(x+1\right)\sqrt{2x+1}=0\)
c) \(\frac{\sqrt{x+1}-2}{\sqrt[3]{2x+1}-3}=\frac{1}{x+2}\)
d) \(-2x^3+10x^2-17x+8=2x^2\sqrt[3]{5x-x^2}\)
e) \(9x^2-28x+21=\sqrt{x-1}\)
f) \(3x\left(2+\sqrt{9x^2+3}\right)+\left(4x+2\right)\sqrt{1+x+x^2}+1=0\)
Mng giúp em với ạ, em cảm ơn
Tìm x biết
1) \(\sqrt{x-1}=3\)
2) \(\sqrt{x}-\sqrt{3}=0\)
3) \(4-5\sqrt{x}=-1\)
4) \(\sqrt{x}\left(\sqrt{ }x-1\right)=0\)
5)\(\left(\sqrt{ }x-2\right)\left(\sqrt{ }x+3\right)=0\)
6) \(\left(\sqrt{ }x+1\right)\left(\sqrt{ }x+2\right)=0\)
7) \(^{^{ }}x2+2\sqrt{2x}+2=1\)
Giải phương trình:
a) \(\sqrt{\left(x+1\right)^2}=2\)
b) \(\sqrt{9\left(2x+1\right)^2}=3\)
c) \(2\sqrt{\left(x+1\right)^2}=0\)
d) \(\sqrt{\left(x-1\right)^2}=-1\)
Bài 1: giải các PT sau
a) \(2\sqrt{x}=6\)
b) \(4-5\sqrt{x}=-1\)
c) \(4\sqrt{x}=-3\)
d) \(\sqrt{x}\left(\sqrt{x}-2\right)=0\)
e) \(\left(\sqrt{x}+1\right)\left(\sqrt{x}-3\right)=0\)
f) \(\left(\sqrt{x}+\sqrt{2}\right)\left(\sqrt{x}+3\right)=0\)
Bài 2:
\(9\left(x+2\right)^2-108=0\)
\(P=\left(\dfrac{3x+3\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}+\dfrac{1}{\sqrt{x}+2}-\dfrac{\sqrt{x}-2}{\sqrt{x}-1}\right):\dfrac{\sqrt{x}}{\sqrt{x}+1}\)
a) Rút gọn P (x > o, x khác 1)
b) Tìm giá trị của x để P > 0
Giải phương trình
a, \(\sqrt{x^2-x+9}=2x+1\)
b. \(\sqrt{5x+7}-\sqrt{x+3}=\sqrt{3x+1}\)
c. \(x^2-3x-10+3\sqrt{x.\left(x-3\right)}=0\)
d. \(\sqrt{2-x}+\sqrt{4-x}=x^2-6x+11\)
e. \(x+6\sqrt{x+8}+4\sqrt{6-2x}=27\)
Rút gọn biểu thức:
a) \(A=\left(\frac{3x-3\sqrt{x}-3}{x+\sqrt{x}-2}+\frac{1}{\sqrt{x}-1}-\frac{1}{\sqrt{x}+2}\right):\frac{1}{\sqrt{x}+2}\left(x\ge0,x\ne1\right)\)
b) \(B=\frac{x\sqrt{x}-3}{x-2\sqrt{x}-3}-\frac{2\left(\sqrt{x-3}\right)}{\sqrt{x}+1}+\frac{\sqrt{x}+3}{3-\sqrt{x}}\left(x>0,x\ne9\right)\)
c) \(C=\frac{2\sqrt{x}-9}{x-5+6}-\frac{\sqrt{x}+3}{\sqrt{x}-2}-\frac{2\sqrt{x}+1}{3-\sqrt{x}}\left(x\ge0,x\ne4,x\ne9\right)\)