Question

giải phương trình:

\(7x^2-4x-3=0\)

Answer 1

\(7x^2-4x-3=0\\ \Leftrightarrow7x^2-7x+3x-3=0\\ \Leftrightarrow7x\left(x-1\right)+3\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(7x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-1=0\\7x+3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{3}{7}\end{matrix}\right.\)

Vậy ...

Answer 2

7x2−4x−3=0⇔7x2−7x+3x−3=0⇔7x(x−1)+3(x−1)=0⇔(x−1)(7x+3)=0⇔[x−1=07x+3=0

Answer 3

Lời giải

7x2−4x−3=0⇔7x2−7x+3x−3=0⇔7x(x−1)+3(x−1)=0⇔(x−1)(7x+3)=0⇔[x−1=07x+3=0⇔⎡⎣x=1x=−37