`|2x-1|+|x-1|=x`
`<=>|2x-1|+|1-x|=x`
Áp dụng BĐT:`|A|+|B|>=|A+B|`
`=>|2x-1|+|1-x|>=|2x-1+1-x|=|x|>=x`
Dấu "=" `<=>` $\begin{cases}(2x-1)(1-x) \geq 0\\x \geq 0\end{cases}$
`<=>` $\begin{cases}\dfrac12 \leq x \leq 1\\x \geq 0\end{cases}$
`<=>1/2<=x<=1`
Vậy `S={x|1/2<=x<=1}`