Câu 3:
a) \(n_{Al}=\dfrac{m}{M}=\dfrac{16,2}{27}=0,6\left(mol\right)\)
PTHH: \(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)
0,6--->0,45---->0,3 (mol)
b) \(V_{O_2\left(\text{đ}ktc\right)}=n.22,4=0,45.22,4=10,08\left(l\right)\)
c) \(m_{Al_2O_3}=n.M=0,3.102=30,6\left(g\right)\)