16x2+24xy+9y2=(4x)2+2*4x*3y+(3y)2=(4x+3y)2=[4x-(-3)y]2
=> giá trị của m là -3
\(16x^2+24xy+9y^2=\left(4x-my\right)^2\)
\(\Leftrightarrow\left(4x\right)^2+2\times4x\times3y+\left(3y\right)^2=\left(4x-my\right)^2\)
\(\Leftrightarrow\left(4x+3y\right)^2=\left(4x-my\right)^2\)
\(\Rightarrow m=-3\)
\(16x^2+24xy+9y^{^2}=\left(4x\right)^2+2.4x.3y+\left(3y\right)^2=\left(4x+3y\right)^2\)Dễ thấy -my=3y
=>-m=3
=>m=-3
16\((x)^{2}\)+24xy+9\((y)^{2}\)=\((4x)^{2}\)+2.(4x).(3y)+\((3y)^{2}\)=\((4x+3y)^{2}\) .
\(\Rightarrow\)\((4x-my)^{2}\)=\((4x+3y)^{2}\).
\(\Rightarrow\)-m=3.
\(\Rightarrow\)m=-3
giai ho mk nha
