Giải hộ mình bài toán với
Câu 1 :
\(\dfrac{3}{35}\) - ( \(\dfrac{3}{5}\)+x ) = \(\dfrac{1}{2}\)
=> \(\dfrac{3}{5}\)+x = - \(\dfrac{29}{70}\)
=> x = \(\dfrac{-71}{70}\)
Câu 2 :
\(\dfrac{1}{2}\)x-\(\dfrac{1}{3}\)= \(\dfrac{1}{4}\)x -\(\dfrac{1}{6}\)
=> \(\dfrac{1}{2}\)x -\(\dfrac{1}{4}\)x = \(\dfrac{-1}{6}\)+\(\dfrac{1}{3}\)
=> x.(\(\dfrac{1}{2}\)-\(\dfrac{1}{4}\)) = \(\dfrac{1}{6}\)
=> x.\(\dfrac{1}{4}\)=\(\dfrac{1}{6}\)
=> x =\(\dfrac{2}{3}\)
Câu 3 :
1\(\dfrac{3}{4}\) x +\(\dfrac{11}{2}\)=\(\dfrac{-4}{5}\)
=>\(\dfrac{7}{4}\)x = \(\dfrac{-63}{10}\)
=>x =\(\dfrac{-18}{5}\)
Câu 4:
(2x-1)2-5 = 20
=>(2x-1)2 =25
=> (2x-1)2= 52
=> 2x-1 = 5
=> 2x= 6
=> x= 6:2
=> x =3
Câu 5 :-\(\dfrac{3}{4}\)-|\(\dfrac{4}{5}\)-x | =-1
=> | \(\dfrac{4}{5}\) - x | = \(\dfrac{1}{4}\)
=> \(\dfrac{4}{5}\)-x = \(\dfrac{1}{4}\) hoặc \(\dfrac{4}{5}\)-x =\(\dfrac{-1}{4}\)
+) \(\dfrac{4}{5}\)-x = \(\dfrac{1}{4}\)=>x=\(\dfrac{11}{20}\)
+) \(\dfrac{4}{5}\) -x = \(\dfrac{-1}{4}\)=> x=\(\dfrac{21}{20}\)
Vậy .......................
