HPT
\(\Leftrightarrow\left\{{}\begin{matrix}2x^2=\left(x+1\right)^2+\left(y-1\right)+3y+3\\\left(x+1\right)^2+\left(y-1\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x+1\right)^2+\left(\frac{2x^2-3}{3}-1\right)=0\\y=\frac{2x^2-3}{3}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}5x^2+6x-3=0\left(1\right)\\y=\frac{2x^2-3}{3}\left(2\right)\end{matrix}\right.\)
Toi day use delta o (1) la xong