Question

Giá trị x thỏa mãn \(\frac{x-3}{2-x}\)=\(\frac{2}{3}\)

tìm x

Answer 1

\(\frac{x-3}{2-x}=\frac{2}{3}\)

\(3\left(x-3\right)=2\left(2-x\right)\)

\(3x-9=4-2x\)

\(3x+2x=4+9\)

\(5x=13\)

\(x=\frac{13}{5}\)

Answer 2

\(\frac{x-3}{2-x}=\frac{2}{3}\)

\(\Rightarrow3.\left(x-3\right)=2.\left(2-x\right)\)

\(\Rightarrow3.x-9=4-2x\)

\(\Rightarrow3x+2x=4+9\)

\(\Rightarrow5x=13\)

\(\Rightarrow x=\frac{13}{5}\)

Answer 3

\(\frac{x-3}{2-x}\) = \(\frac{2}{3}\)

=> 3(x-3) = 2(2-x)

3x-9 = 4 -2x

3x+2x = 4+9

5x = 13 

=> x = \(\frac{13}{5}\)