Ta có:
\(x^4=\left(\dfrac{1}{4}\right)^2\\ hay:x^4=\left(\left(\dfrac{1}{2}\right)^2\right)^2\\ \Rightarrow x^4=\left(\dfrac{1}{2}\right)^4\\ \Rightarrow x^4=\left(\pm\dfrac{1}{2}\right)^4\\ \Rightarrow x=\pm\dfrac{1}{2}\)
Vì x dương nên: \(x=\dfrac{1}{2}\)
Ta có bài toán:
\(x^4=\left(\dfrac{1}{4}\right)^2\)
\(x^4=\dfrac{1}{16}\)
\(x=\sqrt[4]{\dfrac{1}{16}}\)
\(x=\dfrac{1}{2}\)
Ta co \(x^4=\left(\dfrac{1}{4}\right)^2\)
\(=>x^4=\dfrac{1}{16}\)
\(=>x^4=\left(\dfrac{1}{2}\right)^4\)
\(=>x=\dfrac{1}{2}\) hoặc \(\dfrac{-1}{2}\)
Vậy x ={\(\dfrac{-1}{2};\dfrac{1}{2}\)}
tick cho mk nha
