\(\dfrac{x^2+2}{\sqrt{x^2+1}}=\dfrac{x^2+1+1}{\sqrt{x^2+1}}=\dfrac{\left(\sqrt{x^2+1}\right)^2}{\sqrt{x^2+1}}+\dfrac{1}{\sqrt{x^2+1}}\)
\(=\sqrt{x^2+1}+\dfrac{1}{\sqrt{x^2+1}}\ge2\sqrt{\sqrt{x^2+1}.\dfrac{1}{\sqrt{x^2+1}}}=2\)
Dấu "=" xảy ra khi x = 0