Từ \(\frac{x+5}{2014}+\frac{x+6}{2013}+\frac{x+7}{2012}=-3\)
\(\Leftrightarrow\left(\frac{x+5}{2014}+1\right)+\left(\frac{x+6}{2013}+1\right)+\left(\frac{x+7}{2012}+1\right)=0\)
\(\Leftrightarrow\frac{x+2019}{2014}+\frac{x+2019}{2013}+\frac{x+2019}{2012}=0\)
\(\Leftrightarrow\left(x+2019\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}\right)=0\)
\(mà\) \(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}>0\)
nên : \(x+2019=0\Leftrightarrow x=-2019\)
Vậy : \(x=-2019\)
\(\frac{x+5}{2014}+\frac{x+6}{2013}+\frac{x+7}{2012}=-3\\ \frac{x+5}{2014}+\frac{x+6}{2013}+\frac{x+7}{2012}+3=0\\ \left(\frac{x+5}{2014}+1\right)+\left(\frac{x+6}{2013}+1\right)+\left(\frac{x+7}{2012}+1\right)=0\\ \frac{x+2019}{2014}+\frac{x+2019}{2013}+\frac{x+2019}{2012}=0\\ \left(x+2019\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}\right)=0\\ \Rightarrow x+2019=0\\x=-2019 \)
Vậy x = -2019
