Có: \(\frac{x+1}{5}=\frac{2-x}{3}\)
\(\rightarrow3\left(x+1\right)=5\left(2-x\right)\)
\(\rightarrow3x+3=10-5x\)
\(\rightarrow3x+5x=10-3\)
\(\rightarrow8x=7\)
\(\Rightarrow x=\frac{7}{8}\)
Nhớ tick mik nha
\(\frac{x+1}{5}=\frac{2-x}{3}\\ \Leftrightarrow3x+3=10-5x\\ 3x+5x=10-3\\ 8x=7\\ x=\frac{7}{8}\)
x+15= MTC : 15
\(\Leftrightarrow\) \(3(x+1)\) = \(5(2-x)\)
\(\Leftrightarrow\) \(3x+3 = 10 - 5x\)
\(\Leftrightarrow\) \(3x+5x = 10 - 3\)
\(\Leftrightarrow\) \(8x= 7 \)
\(\Leftrightarrow\)\(x = \dfrac{7}{8} \)