\(\frac{a}{b}=\frac{c}{d}\Leftrightarrow ad=bc\)
Áp dụng kiến thức trên ta có:
\(\frac{x}{-2}=-\frac{8}{x}\Leftrightarrow x.x=\left(-8\right).\left(-2\right)=16\)
\(\Leftrightarrow x^2=16\rightarrow x\in\left\{-4;4\right\}\)
Ta có:
\(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x.x=\left(-2\right).\left(-8\right)\Rightarrow x^2=16=4^4\Rightarrow x=4\)
\(\frac{x}{-2}\)= \(\frac{-8}{x}\)= x.x= -8.-2= x.x= 16=> x=4